Answer:
2.5833333333333333333
Step-by-step explanation:
Im not 100 percent positive that this is correct but I think the answer is
184
Answer:
The answer is 4
Step-by-step explanation:
Given:
One of the legs of a right triangle is 9 cm.
The area of the triangle is 225 cm².
To find:
The length of the other leg.
Solution:
The area of a triangle is
![Area=\dfrac{1}{2}\times Base\times Height](https://tex.z-dn.net/?f=Area%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20Base%5Ctimes%20Height)
The area of a right triangle is
![Area=\dfrac{1}{2}\times (leg_1)\times (leg_2)](https://tex.z-dn.net/?f=Area%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%28leg_1%29%5Ctimes%20%28leg_2%29)
Let x be the length of other leg.
![225=\dfrac{1}{2}\times (9)\times (x)](https://tex.z-dn.net/?f=225%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%289%29%5Ctimes%20%28x%29)
![2\times 225=9x](https://tex.z-dn.net/?f=2%5Ctimes%20225%3D9x)
![\dfrac{450}{9}=x](https://tex.z-dn.net/?f=%5Cdfrac%7B450%7D%7B9%7D%3Dx)
![50=x](https://tex.z-dn.net/?f=50%3Dx)
Therefore, the length of the other leg is 50 cm.
-3 + 3n = -6 - 6n. Expand the brackets
3n + 6n = -6 + 3. Collect like terms
9n = -3
n = -3/9 = -1/3