Answer:
A) Vol_10_cubes = 2*(5^4) inch^3
B) Area_10_cubes = (2^2)*3*(5^3) inch^2
Step-by-step explanation:
A)The volume of a cube, as all sides are equal:
Vol_cube = (side)^3
side = 5 inches
Vol_cube = 5^3 inch^3
Since we have 10 cubes
10 = 2*5
Vol_10_cubes = 2*(5^4) inch^3
B) A cube has six faces, each with area equal to its squared side
Area_cube = 6*(side)^2
Area_cube = 6*(5)^2 inch^2
Area_10_cubes = 2*5*6*(5)^2 inch^2
Area_10_cubes = (2^2)*3*(5)^3 inch^2
Answer:
D. 20
Step-by-step explanation:
13 - 2 (1-15) ÷ 4
First deal with whatever in the parentheses
13 - 2 (-14) ÷ 4
Multiply and divide from left to right
13 - (-28) ÷ 4
13 - (-7)
The negatives would cancel so add 13 and 7 to get 20
Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,

Answer:53.38 is the answer
Step-by-step explanation:
The radius is always half of the diameter so half of 17 is 8.5. 8.5x3.14 is 26.69. Then you add 26.69+26.69 to get the answer. (I’m not positive that this is correct)
Answer:
x= 3
y=2
Step-by-step explanation:
-3x + 9y = 9 ----------- equation 1
3x + 2y = 13--------------- equation 2
In Matrix Form
Let A =
X =
and B =
Then Mathematically AX= B
or X= A⁻¹ B
Where A⁻¹ = Adjacent A/ mod of A
Adjacent A =
Mod Of A= -6 - (27) = -33 which is not equal to zero
so Putting These values in the given formula
X= 1/-33
Now Multiplying Rows and Columns
= -1/33 ![\left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%2A9%2B-%209%2A13%5C%5C-3%2A9%20%2B-%203%2A13%5Cend%7Barray%7D%5Cright%5D)
Solving the Matrix we get
= -1/33 ![\left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D18-117%5C%5C-27-39%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= -1/33 ![\left[\begin{array}{cc}-99\\-66\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-99%5C%5C-66%5Cend%7Barray%7D%5Cright%5D)
From Here we find x= 99/33 or 3
and y = 66/33= 2