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gavmur [86]
3 years ago
11

Please help ASAP if you can answer all I will mark brainliest, I have also added extra points! (No need to explain the answer wi

th solution just type the answer for each question) ☺️

Mathematics
1 answer:
krok68 [10]3 years ago
4 0
1. 9
2. x = 7
3. 12
4. 7.12
5. 3
6. 1.2
7. 41.48
8. I cant see the numbers, can you make the photo bigger
9. again i cant see, can you make it bigger
10. 37,260
16. 7.4
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The answer is 1,57,940,000

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Numbers that are palindromes read the same forward and backward. For​ example, 30203 is a​ five-digit palindrom. If a single num
nirvana33 [79]
For a two-digit number to be palindromic, the two digits must be the same.

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Total number of two-digit numbers is 90.

Therefore, the <span>probability that a randomly chosen​ two-digit number is palindromic is 1 / 10 or 0.1.</span>
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3 years ago
11x-2 can you solve for xplzz
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Any other information?
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3 years ago
Read 2 more answers
How many dots would be in the 6th picture?
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4 years ago
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Based on data from a​ college, scores on a certain test are normally distributed with a mean of 1530 and a standard deviation of
harkovskaia [24]

Answer:

0.73% of the scores are greater than 2317.

14.46% of the scores are less than 1190.

38.23% of the scores are between 1351 and 1673.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1530, \sigma = 322

Find the percentage of scores greater than 2317.

This is 1 subtracted by the pvalue of Z when X = 2317. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{2317 - 1530}{322}

Z = 2.44

Z = 2.44 has a pvalue of 0.9927.

So 1-0.9927 = 0.0073 = 0.73% of the scores are greater than 2317.

Find the percentage of scores less than 1190.

This is the pvalue of Z when X = 1190. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1190 - 1530}{322}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446.

So 14.46% of the scores are less than 1190.

Find the percentage of scores between 1351 and 1673.

This is the pvalue of Z when X = 1673 subtracted by the pvalue of Z when X = 1351. So

X = 1673

Z = \frac{X - \mu}{\sigma}

Z = \frac{1673- 1530}{322}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

X = 1351

Z = \frac{X - \mu}{\sigma}

Z = \frac{1351- 1530}{322}

Z = -0.56

Z = -0.56 has a pvalue of 0.2877

So 0.67-0.2877 = 0.3823 = 38.23% of the scores are between 1351 and 1673.

4 0
3 years ago
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