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SVEN [57.7K]
2 years ago
8

Please help!! shirley is drawing triangle that have the same area

Mathematics
2 answers:
Aliun [14]2 years ago
6 0

Answer:

\boxed{12 \: \mathrm{and} \: 7}

Step-by-step explanation:

Solve for the area of first triangle.

\frac{bh}{2}

b=base\\h=height

\frac{14 \times 6}{2}

\frac{84}{2} =42

The area of second triangle is same as the first triangle.

The area of second triangle is 42 units².

The base varies inversely with the height.

b \propto \frac{1}{h}

As the value of <em>b</em> increases, the value of <em>h</em> decreases.

\frac{12 \times 7}{2}=42

The answer is <em>b</em> = 12 and <em>h</em> = 7.

natima [27]2 years ago
4 0

Answer:

12 and 7

Step-by-step explanation:

The area of the first  triangle is

A = 1/2 bh

A = 1/2 ( 14*6)

A = 42

The area of the second triangle must equal 42

Varying inversely means as the height increases, the base must decrease at the same rate

Lets try 12 and 7

A = 1/2 (12*7)

A = 42

The height of the new triangle increased and the base decreased

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After 6 years, the hourly rate should be 34.69 (or something around that since you may want to round)
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3 years ago
Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94
ra1l [238]
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3 0
3 years ago
Vail Resorts pays part-time seasonal employees at ski resorts on an hourly basis. At a certain mountain, the hourly rates have a
notsponge [240]

Answer:

z=0.842

And if we solve for a we got

\mu=13.16 +0.842*3=15.69

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the hourly rates of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,3)  

For this part we want to find a value a, such that we satisfy this condition:

P(X>13.16)=0.20   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.20

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.842

And if we solve for a we got

\mu=13.16 +0.842*3=15.69

3 0
2 years ago
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nata0808 [166]

Answer:

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Step-by-step explanation:

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