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stellarik [79]
4 years ago
14

What construction does the image below demonstrate?

Mathematics
2 answers:
uranmaximum [27]4 years ago
8 0
The construction below demonstrates a hexagon inscribed in a circle.
PtichkaEL [24]4 years ago
7 0

Answer:

The construction depicts the inscribing of a hexagon in a circle.

Step-by-step explanation:

These are the following steps to inscribe a hexagon in a circle.

1. We mark a point anywhere on the circle. This mark is the first vertex of the hexagon.

2. Now we will set the compass on this vertex and set the width to the center of the circle. This is the radius of the circle.

3. Now we will make an arc across the circle which is the next vertex of the hexagon.

4. Now moving the compass on to the next vertex and drawing another arc, which becomes the third vertex of the hexagon.

5. Repeat step 4 until all vertices are marked.

6. Lastly, we will draw a line between each successive pairs of vertices, for a total of six lines.

Now we can see a hexagon inscribed in a circle.

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R+3.2=6.1<br> What is the value of r? Show work
ankoles [38]
Hello,

The answer is 2.9.

Reason:

Solve this two ways:

1. You could be just regularly solving the question but subtracting 6.1 to 3.2.

6.1-3.2=2.9

2. Or you could be solving variable.

Subtract 3.2 on both sides:

6.1-3.2=2.9

r=2.9

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
4 0
3 years ago
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What is the distance between the points (−3, 4) and (−3, −5)?
SVEN [57.7K]

Answer:

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Step-by-step explanation:

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3 years ago
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If sec thita . sin thita =0,then find the value of thita
Rus_ich [418]

Answer:

\large\boxed{\theta=k\pi,\ k\in\mathbb{Z}}

Step-by-step explanation:

\sec\thets\cdot\sin\theta=0\iff \sec\theta=0\ \vee\ \sin\theta=0\\\\\sec\theta\neq0\ \text{for any value of}\ \theta\\\\\sin\theta=0\Rightarrow\theta=k\pi\ \text{where}\ k\in\mathbb{Z}

6 0
3 years ago
In the diagram below, points A, E, and F lie on the same line. If ABCDE is a regular pentagon, and \angle EFD=90^\circ, then how
mash [69]

The measure of ∠FDE = 18°

<u>Explanation:</u>

A Pentagon has 5 sides and is made of 3 triangles

So, sum of the interior angles of the triangle = 180°

Therefore, the total interior angle of a regular pentagon = 3 X 180° = 540°

A regular pentagon will have all its angle equal

All the five angles would make 540°

Let the measure of one angle = x

So,

5x = 540°

x = 108°

Therefore, the measure of each angle of a pentagon is 108°

From the diagram,

∠AED + ∠FED = 180°

∠AED = 108° as it is one of the sides of the pentagon

So,

108° + ∠FED = 180°

∠FED = 72°

In ΔEFD,

∠FED + ∠EFD + ∠FDE = 180°

72° + 90° + ∠FDE = 180°

∠FDE = 18°

Therefore, the measure of ∠FDE = 18°

8 0
3 years ago
bill bought a set of golf clubs for 1700 he has 6 months to pay off his balance after paying a down payment. bill makes payment
solmaris [256]
$1700 - 201(6) = 494
His down payment was $494.00
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3 years ago
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