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3 years ago

The high temperature one day was 30°F. Then

1 answer:

5 0

Yes because when you subtract a number, you can also say that you added a negative. So if it dropped 23 degrees, then you also added -23 degrees

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PLS HELP! WILL GIVE BRAINLIEST IF U SOLVE!!

tatyana61 [14]

Answer:

1st row =-4

2nd row = 2,-2(from left)

3rd row= -2,-1,2

4th row= -2,1,-1,-2

5th row = 2,-1,-1,1,-2

3 0

2 years ago

Please help me with number 7.

Neko [114]

7a expression: 12 + (- 1) + (- 1) + 3
7b evaluate: 13 Solving:((12 + -1 = 11) + (-1 + 3 = 2) (11 + 2 = 13))
7c: At the end of the three days, the value of the stock was $13.

6 0

3 years ago

Y=x^2+8<br> Find the Domain, explain your answer

alekssr [168]

Step-by-step explanation:

look at the attachment above ☝️

3 0

2 years ago

A 5 mile jogging path diagonal divides a rectangular park in half. The park is 4 miles long. Find the width of the park.

levacccp [35]

Answer: The required width of the park is 3 miles.

Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.

We are to find the width of the park.

As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,

where length DA = 5 miles, BD = 4 miles and AB = width = ?

Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.

Using Pythagoras theorem in triangle ABD, we have

$BD^2=AB^2+DA^2\\\\\Rightarrow AB=\sqrt{BD^2-DA^2}\\\\\Rightarrow AB=\sqrt{5^2-4^2}\\\\\Rightarrow AB=\sqrt{25-16}\\\\\Rightarrow AB=\sqrt{9}\\\\\Rightarrow AB=3.$

Thus, the required width of the park is 3 miles.

7 0

3 years ago

The length of a rectangle is 7 centimeters greater than the width.

Lisa [10]

Answer:

length = 17cm, width = 10cm

Step-by-step explanation:

2L + 2w = 54

L = w + 7

Substitute:

2(w + 7) + 2w = 54

2w + 14 + 2w = 54

4w = 40

w = 10

L = 10 + 7 = 17

7 0

3 years ago