Answer:
6x² - 10x + 11
Step-by-step explanation:
Step 1: Write expression
(9x² - 6x) + (5 - 4x) + (6 - 3x²)
Step 2: Combine like terms
6x² - 10x + 11
8n+16
the four odd numbers are 2n+1, 2n+3, 2n+5, 2n+7
2n+1+2n+3+2n+5+2n+7=8n+16
How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
sveta [45]
There are 6 digits. Each digit can take ten different numbers except for the first digit since it cannot be zero.
So:
9 x 10 x 10 x 10 x 10 x 10
900000 numbers.
Another way of thinking about this is to just count up to 999,999. Obviously there are 999,999 different numbers here. But since our number has to have 6 digits in them, we have to delete 99,999 numbers. Thus there are 900,000 different numbers.
The answer is B I agree with him/her
