Question

2.05 MC) Triangles ABC and DEF. Coordinates for A are 0, 2, for B 2, 4, and for C 1, negative 2. Given: ΔABC ≅ ΔEFD What is the length of Segment line FE rounded to the nearest tenth? (4 points) 2.8 3.4 4.1 6.1

Answer 1

Answer:

2.8

Step-by-step explanation:

From the congruence statement, we see that AB corresponds with EF; this means they will be congruent.

To find the measure of FE, we will find the distance between points A and B using the distance formula:

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Using our coordinates for A and B, we have

$A(0,2)\text{and }B(2, 4)\\\\d=\sqrt{(4-2)^2+(2-0)^2}=\sqrt{2^2+2^2}\\\\=\sqrt{4+4}=\sqrt{8}=2.828427\approx 2.8$

Answer 2

The answers is 2.8 and or 2.83 which ever your answer chose is