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elixir [45]
3 years ago
8

If a segment of one of the DNA strands being replicated consists of CGAATG, what will be the base sequence of the corresponding

DNA strand?
Biology
1 answer:
geniusboy [140]3 years ago
3 0

Answer: GCTTAC

Explanation: Adenine (A) always pair with thymine (T), guanine (G) always pair with cytosine (C).

So when DNA replicates, complementary strand always recognizes the bases of the template strand in this manner. DNA polymerase helps in the synthesis of two strands in pair.

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From approximately 240 to 66 million years ago, dinosaurs dominated most of the land habitats on Earth. Around 66 million years
Harlamova29_29 [7]

The correct answer is option C, that is, mammals were able to diversify to make use of the variety of habitats that were previously occupied by dinosaurs.

Adaptive radiation refers to the comparatively fast evolution of various species from a single common ancestor. Adaptive radiation usually takes place when a species enters a novel area and distinct traits influence its existence. An illustration of adaptive radiation is the progression of mammals after the annihilation of dinosaurs.  


3 0
2 years ago
Which of the following would NOT increase (whole body) oxygen consumption during recovery from exercise and increase excess post
Harrizon [31]

Answer:

(B) None of the answers are true...

Explanation:

(A) is wrong because the high levels of epinephrine promote activation of sympathetic nervous system that'll ultimately increase oxygen consumption.

(C) Elevated temperatures of body require immediate cooling that's why breathing rate gets high and ultimately the oxygen consumption.

(D) We all know that a vigorous dose of exercise always increases your bodies oxygen consumption.

3 0
3 years ago
How long do butterflies live?
Arturiano [62]
Every species has different timespans. Some butterflies live 6 months, other live 7 years. However, most of their time they are caterpillars or are in a coccoon. Up to 6 years
6 0
3 years ago
Read 2 more answers
The potential energy stored in the nucleus of an atom is
Verdich [7]

Answer:

Nuclear energy

Explanation:

6 0
3 years ago
A normal breath takes in about 1.0 L of air. If air has an average molar mass of 28.8 g per 1 mol and has a density of 0.97 g/mL
Ann [662]

Taking into account the definition of density and Avogadro's Number, you take 2.0286×10²⁵ molecules of air.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

<h3>What is Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of molecules of air</h3>

In this case, you know that:

  • Density= 0.97 \frac{g}{mL}
  • Volume= 1 L= 1000 mL

Replacing in the definition of density:

0.97 \frac{g}{mL}=\frac{mass}{1000 mL}

Solving:

mass= 0.97 \frac{g}{mL}  ×1000 mL

<u><em>mass= 970 g</em></u>

Air has an average molar mass of 28.8 g per 1 mol. Then 970 grams are contained in 33.68 moles.

Now, considering the definition of Avogadro's number you can apply the following rule of three: If 1 mole of air contains 6.023×10²³ molecules, 33.68 moles contains how many molecules?

amount of molecules = (33.68 moles× 6.023×10²³ molecules)÷ 1 mole

<u><em>amount of molecules= 2.0286×10²⁵ molecules</em></u>

Finally, you take 2.0286×10²⁵ molecules of air.

Learn more about

density:

brainly.com/question/952755

brainly.com/question/1462554

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ11

4 0
1 year ago
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