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velikii [3]
3 years ago
6

The 8th grade class had a fundraiser for a ckasspriject. The class set a goal to raise $300. They charge $5.00 for each car they

washed. They have collected 65% of their goal so far. How many more cars must they wash to reach the goal
Mathematics
1 answer:
Inga [223]3 years ago
3 0
Answer = 21 cars.

First we need to find out how many cars they have to wash in total. To do that we need to divide 300 by 5. 300÷5 = 60.
Since we know that they've collected 65% of their goal, we need to find 65% of 60. 65% of 60 = 39.
Now we know that they've already washed 39 cars, so we need to subtract 39 from their entire goal of 60 cars. 60-39 = 21 cars.

-Hope it helps!
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3 years ago
WILL GIVE BRAINLIEST!!!!
boyakko [2]

Exponential functions are known to increase geometrically. An example of exponential function is  p(x) = 500(1.02)^x

<h3>Exponential functions</h3>

Exponential functions are known to increase geometrically. The standard exponential function is given as:

y = ab^x

a is the base

x is the exponent

From the given options, the function written in this form is

p(x) = 500(1.02)^x. Hence an example of exponential function is

p(x) = 500(1.02)^x

Learn more on exponential function here: brainly.com/question/12940982

#SPJ1

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3 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ&gt;0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\&#10;\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\&#10;\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\&#10;\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\&#10;\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\&#10;\mathsf{17\,sin^2\,\theta=1}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

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