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d1i1m1o1n [39]
3 years ago
11

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = -2/3–x + 6. What is the point-slope

form of the equation for this line?
A. y – 3 = –2/3(x + 8)
B. y + 3 = –2/3(x – 8)
C. y + 8 = –2/3x – 3)
D. y – 8 = –2/3(x + 3)
Mathematics
1 answer:
lilavasa [31]3 years ago
8 0
The correct answer is d
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What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}
\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
\end{tabular}

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
4 0
3 years ago
Evaluate the expression for the given value of the variable 5 ×(h+3) for h=7
Bad White [126]

Answer:

<h2>50</h2>

Step-by-step explanation:

Put h = 7 to the expression 5 · (h + 3):

5\cdot(7+3)=5\cdot10=50

5 0
2 years ago
Can anyone help me with this problem by factoring and list the steps please
jok3333 [9.3K]

Answer:

m=2, m=0

-ˋˏ✄┈┈┈┈┈┈┈┈┈┈┈┈┈

20m^2-40m=0

<u>Use quadratic formula:-</u>

᠃ ⚘᠂ ⚘ ˚ ⚘ ᠂ ⚘ ᠃

m_1,_2=\frac{-(-40) -+\sqrt{x} (-40)^2-4*20*0}{2*20}

\sqrt{(-40)^2-4*20*0}=40

m_1,_2=\frac{-(-40)-,+40}{2*20}

m_1=\frac{-(-40)+40}{2*20},m_1=\frac{-(-40)-40}{2*20}

m=\frac{-(-40)+40}{2*20}:2

m=\frac{-(-40)-40}{2*20}:0

m=2, m=0

˱   ┈  ┈  ┈  ┈   ˲

hope it helps...

have a great day!!

6 0
2 years ago
.......... is the slope zero
Eddi Din [679]

Answer:


Step-by-step explanation:

OK... You have to use this formula: <u>Y2 - Y1</u>

                                                          X2 - X1

  • -2 represents X1
  • 7 represents Y1
  • 2 represents X2
  • -5 represents Y2    

<u>Y2 - Y1</u>

X2 - X1

<u>-5 - 7</u>

2 - - 2

<u>-12</u>

-2

Simplify by dividing both -12 & -2 by 2: <u>-6</u>

                                                                 -1

It's either <u>-6</u> or it's just -6 by itself... Really sorry if I'm wrong...

                -1  




4 0
3 years ago
Read 2 more answers
If an object is rotated clockwise 130° around a center and then counterclockwise 75° around the same center, what is the angle b
Keith_Richards [23]
That would be 130 - 75  = 55 degrees answer
6 0
3 years ago
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