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____ [38]
4 years ago
8

I need help please answers please

Mathematics
1 answer:
motikmotik4 years ago
8 0
We have two points:
(-3,5) and (2,-3)

I
An equation in oint-slope form has this shape:
y-y₀=m(x-x₀)
m=slope

1) we compute the slope (m) between two points:
Given two points (x₁,y₁) and (x₂,y₂) the slope between these pointw will be.
m=(y₂-y₁)/(x₂-x₁)

In this case, our slope would be:
m=(-3-5)/(2+3)=-8/5

2) we choose one of these points and replace it in the equation, the result will be the same:
(-3,5)
<span>y-y₀=m(x-x₀)
</span>y-5=-8/5(x+3)

Answer: y-5=-8/5(x+3)
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The angle θ lies in Quadrant II .
Andreyy89

let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.

cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.


\bf cos(\theta )=\cfrac{\stackrel{adjacent}{-2}}{\stackrel{hypotenuse}{3}}\impliedby \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{3^2-(-2)^2}=b\implies \pm\sqrt{5}=b\implies \stackrel{\textit{II Quadrant}}{+\sqrt{5}=b}~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\sqrt{5}}}{\stackrel{adjacent}{-2}} \\\\\\ ~\hspace{34em}

6 0
4 years ago
g A catering service offers 7 %E2%80%8b Appetizers, 9 main%E2%80%8B courses, and 5 desserts. A banquet committee is to select 2
Feliz [49]

Answer:

945 ways

Step-by-step explanation:

<u>Total</u>

  • Number of Appetizers = 7
  • Number of main courses = 9
  • Number of desserts =5

<u>Required Selection</u>

  • Number of Appetizers = 2
  • Number of main courses = 8
  • Number of desserts =4

2  Appetizers out of 7 can be selected in ^7C_2 ways

8 main courses out of 9 can be selected in ^9C_8 ways

4 desserts out of 5 can be selected in ^5C_4 ways

Therefore, the number of ways this can be done

=^7C_2 \times ^9C_8 \times ^5C_4

=945 ways

5 0
3 years ago
What is the slope of the graph of 2x – 6y = 9?
notsponge [240]
Let's make our equation in the form of y = mx + b

<span> 2x – 6y = 9

Add 6y on both sides

2x = 6y + 9

Subtract 9 on both sides

6y = 2x - 9

Divide 6 on both sides

y = 1/3 - 3/2

Now, we have it in the form of y = mx + b

In y = mx + b, m is the slope and b is the y-intercept

That means in y = 1/3 - 3/2, the slope is A) 1/3.

Your answer is A) 1/3</span>
5 0
3 years ago
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8 0
3 years ago
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Ksenya-84 [330]

Answer:

500w + 25 = 200

Step-by-step explanation:

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8 0
3 years ago
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