5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
To find the perimeter, we must add together the length of each side.
The tick mark on the lines means they are equal, so that means we have two lines that are equal to 10
26 + 10 + 35 + 5 + 10 + (38 - 10) = 114"
If you post your questions we could help
Answer:
isosceles trapezoid
Step-by-step explanation:
1) find the distance of the points
AB = 
BC = |7-4| = 3
CD = 
AD = |9-2| = 7
2) equation of the line that passes threw BC
y = 7
3) equation of the line that passes threw AD
y = 5
conclusion
the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid
