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Firdavs [7]
2 years ago
11

5 x 6 - 5/5 +2 Can somebody help me please

Mathematics
1 answer:
UkoKoshka [18]2 years ago
6 0
5•6=30
30-5/5=29
(5/5=1)
29+2=31
Answer: 31
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What type of counting problem is this? How many different sequences of 3 playing cards (from a single 52-card deck) exist?
n200080 [17]

Answer:

Permutation without repetition

Step-by-step explanation:

The order of the cards matter, which makes it a permutation, but since none of the cards are exactly the same, repetition isn't allowed/possible

7 0
3 years ago
22 gallons of gas cost $65.56 what is the unit rate for one gallon of gas
Kitty [74]
Hey there!

If we would want to find out what it would be, we would have to divide it.

Your correct answer would be (2.98)

I did 65.56/22.

Hope this helps you!
7 0
2 years ago
Read 2 more answers
Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
Help please
Digiron [165]

Answer:

Option C.

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

            = x² + [-(i)²√(13)²]  [Since i = √(-1)]

            = x² - (i√13)²

            = (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]

Option C will be the answer.

7 0
2 years ago
Can someone help me with this
weeeeeb [17]

Answer:i can but what is being asked

Step-by-step explanation:

5 0
2 years ago
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