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3 years ago

One of two complementary angles is 8 degrees less than the other.

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

5 0

Answer: The correct option is

$(A)~~x+y=90,~~x-y=8.$

Step-by-step explanation: Given that one of the two complementary angles is 8 degrees less than the other.

We are to select the correct system of equations represents the given word problem.

Let x and y represents the two complementary angles where y is less than x.

Since one angle is 8 degrees less than the other and y is less than x, so we have

$x-y=8.$

We know that the sum of two complementary angles is 90 degrees, so we get

$x+y=90.$

Thus, the required system of equations representing the given word problem will be

$x+y=90,\\\\x-y=8.$

Option (A) is CORRECT.

Ronch [10]3 years ago

3 0

I think it is the middle one becuase complimentary angles add up to 90 degrees and if one is 8 less than the other it would be proved like that.

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aleksklad [387]

Answer:

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Step-by-step explanation:

5 divided by 2.5 (or 2 1/2)

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3 years ago

Alex took 31 exams for 5 years studying at the MaPhAs University. Each year, he took more exams than the previous year. During h

katen-ka-za [31]

Answer:

The fourth year he took 8 exams

Step-by-step explanation:

We must do it by trial and error:

We must start from the first year:

A = 1 exam

If the first year he took 1 exam, the last year he did 3, but this answer is not possible because the rule that the more the years pass, the more exams he does, is not fulfilled.

A = 2 exams

In this case, if it is true that each year increases, but it does not meet the total rule, since:

Year 1 = 2

Year 2 = 3

Year 3 = 4

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A = 3 exams

Therefore the fifth year would be 9, therefore it would be:

Year 1 = 3

Year 2 = 4

Year 3 = 5

Year 4 = 6

Year 5 = 9

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This means that we are missing 4 units to reach 31, therefore we must add 4 units between years 2, 3 and 4, but always bearing in mind that each year should increase with respect to the previous one.

If we add 2 exams to year 4, 1 exams to year 3 and 1 exam to year 2, we would have the following results:

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3 years ago

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BlackZzzverrR [31]

Answer:

The answer is y = 3x - 6

Step-by-step explanation:

Equation of a line is y = mx + c

Where

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3 years ago

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aniked [119]

Answer:

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Step-by-step explanation:

First we will calculate f(-3):

f(-3) = 2-9*(-3) = 2-(-27) = 2+27 = 29

Therefore, g/f(-3) = (1/29) * (-5+x)(2+x)

Now we will find the values that are not in the domain of g/f:

g/f = [(-5+x)(2+x)]/(2-9x)

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ahrayia [7]

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