Question

a planter box in the city plaza measures 3 2/3 feet by 4/18 feet by 2 1/2 feet. find the volume of the planter box

Answer 1

Answer:

$V=\frac{55}{27}ft^3$

Step-by-step explanation:

We are given box

whose dimensions are

Length is 3 2/3 feet

so,

$L=3\frac{2}{3} =\frac{3\times 3+2}{3}=\frac{11}{3}$

Width is 4/18 feet

$W=\frac{4}{18}$

Height is 2 1/2 feet

so,

$H=2\frac{1}{2} =\frac{2\times 2+1}{2}=\frac{5}{2}$

now, we can find volume

$V=L\times W\times H$

now, we can plug values

$V=\frac{11}{3}\times \frac{4}{18}\times \frac{5}{2}$

now, we can simplify it

and we get

$V=\frac{55}{27}ft^3$

Answer 2

Answer:

The volume of the planter box=$2\frac{1}{27}$ cubic feet.

Step-by-step explanation:

Given the dimensions of planter cuboid box:

Length of planter box =$3\frac{2}{3}$ feet.

Breath of planter box=$\frac{4}{18}$ feet.

Height of planter box=$2\frac{1}{2}$ feet.

Formula used for volume of cuboid box= (length×breath×height).

Plugging the values in above formula for volume,we get

Volume of box= $3\frac{2}{3}$× $\frac{4}{18}$×$2\frac{1}{2}$.

Let us convert mixed fractions in to improper fractions first

Therefore,

$3\frac{2}{3}$ feet= $\frac{11}{3}$

$2\frac{1}{2}$ feet =$\frac{5}{2}$

volume =$\frac{11}{3}$× $\frac{4}{18}$×$\frac{5}{2}$

=$\frac{11 \times 5 \times 4}{3 \times 2 \times 18}$

=$\frac{220}{108}$

=$2\frac{1}{27}$ cubic feet.

Therefore, the volume of the planter box=$2\frac{1}{27}$ cubic feet.