I would put in,
1.Moderate and positive
2.Moderate and negative
3.Weak and positive
4.Strong and negative
Well in order to figure this out is by simple division.
1. you take 359 and divide 63 into that
2. this will come out at 5.698
3. So when it ask's how many times 63 goes into 359 you look for the whole number.
4. So the answer is 5 times 63 goes into 359
Hope this helped!!
The rest of the question is as following
What is the distance from person B to the top of the hill?
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Answer;
The attached figure represents the explanation of the problem.
So, it is required to find the distance BH
It will be calculated as following
∠A = 65° and ∠B = 80°
∴ ∠H = 180° - (65° + 80° ) = 35°
But the side AB = 45
So, we can use the sine rule to find the side BH
![\frac{AB}{sin \ H} = \frac{BH}{sin \ A}](https://tex.z-dn.net/?f=%20%5Cfrac%7BAB%7D%7Bsin%20%5C%20H%7D%20%3D%20%5Cfrac%7BBH%7D%7Bsin%20%5C%20A%7D)
![BH = \frac{sin \ A}{sin \ H} * AB](https://tex.z-dn.net/?f=BH%20%3D%20%20%5Cfrac%7Bsin%20%5C%20A%7D%7Bsin%20%5C%20H%7D%20%2A%20AB)
![BH = \frac{sin \ 65}{sin \ 35} * 45](https://tex.z-dn.net/?f=BH%20%3D%20%20%5Cfrac%7Bsin%20%5C%2065%7D%7Bsin%20%5C%2035%7D%20%2A%2045)
∴ BH ≈ 71.1 feet
∴ The distance from person B to the top of the hill ≈ 71.1 feet
I am not really sure but I have a feeling it’s (B.)
The requested values are found in the attached table
Selected pairs
A(22,160)B(30,172)
find the slope of the line AB
m=(y2-y1)/(x2-x1)=(172-160)/(30-22)=12/8=3/2=1.5m=1.5
one point and slope-------- > A(22.160) m=1.5
y=mx+b
160=1.5(22)+bb=127y=1.5x+127---------- > equation in slope intercept form
<span>If the length of the bone is 12 in------------------ > 12*2.54=30.48 cms
</span>y=1.5x+127- >1.5*30.48+127=172.72 cms
172.72/2.54=68 in
172.72/0.30=575.73 feet
the height estimate of the person before death is 172.72 cms=68 inches=575.73 feet
<span>By the height it could be a man of average height or a tall woman</span>