When the hand moved to 60, the game was over. However, in order to ensure that the game could not be won by a one-point difference in players' scores, the idea of "deuce" was introduced. To make the score stay within the "60" ticks on the clock face, the 45 was changed to 40.
The statement that describes the 3d, 4s, and 4p orbitals of arsenic (as) based on its electronic configuration and position in the periodic table is; The 3d and 4s orbitals are completely filled, and the 4p orbital is partially filled.
The electronic configuration of arsenic is given as; 1s² 2s² 2p^(6) 3s² 3p^(6) 4s² 3d^(10) 4p³.
Now we can see that in that electronic configuration the orbitals are, s, p and D.
Now, the maximum electrons for each of the 3 orbitals are;
Maximum electrons for d orbital = 10 electrons
Maximum electrons for s orbital = 2 electrons
Maximum electrons for p orbital = 6 electrons.
Now, when we compare the maximum number of electrons for each orbital to the ones in electron configuration of arsenic, it is clear from the last 3 orbitals that the 3d and 4s orbitals are completely filled while the 4p orbital is half filled or partially filled.
Read more about electronic configuration at: brainly.com/question/24258336
Answer:
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The number of small cubic blocks that is required to fill the big cubic blocks is 2.
<h3>How to calculate the volume of a cube.</h3>
Mathematically, the volume of a cube is given by the following formula:
Volume of cube = S³
<u>Where:</u>
S is the side length of the cube.
<u>Given the following data:</u>
- Side length of small cube = 1/6 inch.
- Side length of big cube = 2/6 inch.
For the small cube:
Volume of cube = (1/6)³ = 0.5 in³
For the big cube:
Volume of cube = (2/6)³ = 1 in³
Therefore, the number of small cubic blocks that is required to fill the big cubic blocks is given by:
Number = 1/0.5
Number = 2 cubic blocks.
Read more on volume of a cube here: brainly.com/question/25248189
<u>Complete Question:</u>
How many cubic blocks of side length 1/6 inch would it take to fill a cube with a side length of 2/6 inch
