The measure of 1 and 3 would be =90
Alright, so by creating a right triangle with side a, point A, and point P,we can get that a^2+A^2 (if A is the distance from A to P) = P^2 (if P is the distance from P to the rowboat) using the Pythagorean Theorem. After that, we know that he will walk x miles to point B. Since b is A+x, we know that b=A+x and
b-x=A by subtracting x from both sides. Therefore, a^2+(b-x)^2=P^2 and by plugging a=2 and b=8 in, we get 2^2+(8-x)^2=P^2. To find out P, we square root both sides, getting P= sqrt(4+(8-x)^2). Since the man rows 2 miles per hour, we can divide P by 2 to get how much time it takes for him to travel to point P, resulting in sqrt(4+(8-x)^2)/2. In addition, we can divide x by 4 as the man walks 4 miles per hour, getting x/4. Adding them up, we get
sqrt(4+(8-x)^2)/2+x/4 as the amount of time it will take to get to point B
Answer:
7 seconds
Step-by-step explanation:
Ballistic motion is usually modeled in the vertical direction in US customary units by the equation h(t) = -16t^2 +v0·t +h0, where v0 and h0 are the initial velocity and height, and h(t) is the height as a function of time in seconds. For the given initial conditions, the equation of vertical motion will be ...
h(t) = -16t^2 +64t +336
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This question asks you for the value of t for which h(t) = 0. We can solve that equation by factoring.
0 = -16t^2 +64t +336
0 = t^2 -4t -21 . . . . . . . . divide by -16
0 = (t -7)(t +3) . . . . . . . factor the quadratic
t = 7 . . . . . . the positive value of t that makes the equation true
The ball will return to the ground after 7 seconds.
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<em>Additional comment</em>
A graph of the function reveals the ball reaches a maximum height of 400 feet after 2 seconds.
In metric units, the equation is h(t) = -4.9t^2 +v0·t +h0, where distances are in meters instead of feet. Time is still in seconds.
X<span>≥4 . x is greater than or equal to 4
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