HELP ME!!! ITS DUE TOMMOROW!! Find the largest value of $r$ such that $6r^2+7r+8=6$.
2 answers:
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Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.
Indeed, those two numbers are relatively prime.
A.
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.
Indeed, those two numbers are relatively prime.
Answer:
Please refer to the attached graph for the graph of linear inequality:
Step-by-step explanation:
Method to draw graph of inequality:
<u>1. First of all replace the inequality sign with equality.</u>
Now the equation is:
Now, find point and plot them.
Let us put x = 0, we get y = -1. So one point is <em>(0, -1)</em>
Let us put y = 0, we get x = 2. So one point is <em>(2,0)</em>
Now, plot both the point and join with straight line on xy coordinate axis.
2. Now, try to find a random point and put in the inequality.
If the point satisfies the inequality shade the region moving from the line towards that point.
For example:
Taking a point (4, 2)
Putting in the inequality:
So, (4, 2) satisfies the inequality.
Now, shade the region moving from the line towards the point (4,2).
We get the shaded region as shown in the attached figure in the answer area.
