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Nesterboy [21]
3 years ago
5

Helpppppppppp plz for brainliest

Mathematics
2 answers:
Nostrana [21]3 years ago
6 0

Answer:

1)-33/19

2)8/9

3)-43/8

4)1/17

5)-5

Step-by-step explanation:

Plug in the values of (x1 and x2) and (y1 and y2)

Your welcome for doing your homework :)

Vladimir [108]3 years ago
6 0

Answer:

\frac{y2 - y1}{x2 - x1}  \\  \\ 1) \frac{ - 13 - 20}{3 - ( - 16) } \\  \frac{ - 33}{3 + 16}  \\  =  \frac{ - 33}{19}

2) \frac{31 - 23}{27 - 18}  \\  =  \frac{8}{9}

3)\frac{ - 25 - 18}{20 - 12}  \\  =  \frac{ - 43}{8}

4) \frac{21 - 18}{25 - 26}  \\ \frac{3}{ - 1}   \\  =  - 3

5)\frac{11 - 16}{15 - 14}  \\  \frac{ - 5}{1}  \\  =- 5

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3 years ago
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Grace [21]

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Step-by-step explanation:

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6 0
2 years ago
What is the difference between x and dx?
N76 [4]

This response is based upon your having had some background in calculus. "dx" is not introduced before that.

Take a look at the sample function y = f(x) = x^2 + 9. Here x is the independent variable; the dependent variable y changes with x.

Now, for a big jump: we consider finding the area under a curve (graph) between x = a and x = b. We subdivide that interval [a,b] into n vertical slices of area. Each of those slices has its own area: f(x)*dx, where dx represents the width of such subarea. f(x)*dx is the actual subarea. To find the total area under the curve f(x) between x= a and x = b, we add up all of these individual subareas between x = a and x = b. Note that the subinterval width is

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Once again, this all makes sense only if you've begun calculus (particularly integral calculus). Do not try to relate it to earlier math courses.

8 0
3 years ago
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miss Akunina [59]

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3 0
2 years ago
Read 2 more answers
PLEASE HELP!?!?!
nalin [4]
It’s b hope that helped have a great night
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