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Karo-lina-s [1.5K]
4 years ago
7

Compare the following 3/5 and 6/11

Mathematics
1 answer:
Cerrena [4.2K]4 years ago
6 0

Answer: in decimal form, 3/5=0.6 and 6/11=0.54. From this, we can tell that 3/5 is greater than 6/11. I believe this is what you mean by compare them, this is comparing their values.

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How do I do this? Please help!
const2013 [10]

I already answered this question, if you look back in your questions you should find this answered along with another one. I'll do it again just in case you don't find it.

Answer:

{y,x} = {-4,-2}

Expanation:

Solve by Substitution :

// Solve equation [1] for the variable  y

 [1]    y = 2x

// Plug this in for variable  y  in equation [2]

  [2]    -2•(2x) - 8x = 24

  [2]     - 12x = 24

// Solve equation [2] for the variable  x

  [2]    12x = - 24

  [2]    x = - 2

// By now we know this much :

   y = 2x

   x = -2

// Use the  x  value to solve for  y

   y = 2(-2) = -4

8 0
3 years ago
4x-6 + 2x = 18<br> What’s the answer
solmaris [256]

Answer:

x=4

Step-by-step explanation:

4x-6 + 2x = 18

Combine like terms

6x -6 = 18

Add 6 to each side

6x-6+6 =18+6

6x = 24

Divide each side by 6

6x/6 = 24/6

x =4

6 0
4 years ago
Perimeter of triangle:20
goblinko [34]

Answer:

perimeter of rectangle= 2(4+X)

32=8+2x

32-8=2x

26=2x

26/2=X

14=X

perimeter of triangle=3×sides

20=3x

20/3=X

6.66=x

4 0
3 years ago
Help please and thank you
Juliette [100K]

Answer:

infinity

Step-by-step explanation:

you can change x and then every answer will be different

8 0
3 years ago
The area of a triangular block is 81 square inches. If the base of the triangle is twice the height, how long are the base and t
Gre4nikov [31]

Answer:

18 inches and 9 inches

Step-by-step explanation:

Given, The base of a triangle is twice of the height.

Area = 81 sq inches

Let, Base (b) = 2x

Height (h) = x

Area of the triangle = \frac{1}{2}bh

\frac{1}{2}bh = 81

or, x^{2} = 8

Base = 2×9 inches = 18 inches

Height = 9 inches

5 0
2 years ago
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