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3 years ago

Can someone help me with 5 and 6? How do I put it? Will mark brainliest!

Mathematics

2 answers:

OverLord2011 [107]3 years ago

8 0

5.)you write 2+3 (less than symbol) y

6.)then, y+2 $\geq$ 6

Hope this helps you out some!

n200080 [17]3 years ago

5 0

Answer:

2 + 3 < y

y + 2 ≥ 6

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***WILL GIVE MEDAL TO WHOEVER HELPS***

Bezzdna [24]

x+y = 23 and 2x+3y=55; The wording of the answer choices were confusing, but both of these come together to make the correct answer. First, you need x (number of bracelets) + y (number of necklaces) to determine how many of each were sold. Then, you add 2x (cost of each bracelet x bracelets sold) and 3y (same as bracelets but for necklaces). This results in the total amount sold.

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3 years ago

What number can go into 21 and 27

astra-53 [7]

3 only

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3 years ago

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A ball is drawn at random from a box containing 12 red,18

Lubov Fominskaja [6]

Answer:

For a: The probability of getting a red or blue ball is 0.48

For b: The probability of getting a white, blue or orange ball is 0.81

For c: The probability of getting neither white or orange ball is 0.48

Step-by-step explanation:

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}$ .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

For a:

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48$

For b:

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81$

For c:

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52$

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

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3 years ago

If I live 16 minutes away from a movie theater and I need to be there at 5 what time do I leave

TEA [102]

Answer:

4:44 so that you could be there at 5:00 exactly.

Step-by-step explanation:

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3 years ago

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Why is 8(s-3) considered a single term when (s-3) is the difference of two terms?

jok3333 [9.3K]

When you have 8(s-3) you are find a product of 8 times whatever s-3 is however s-3 you are find the difference between whatever s is and 3.

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