Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
Answer:
C (37, 77)
Step-by-step explanation:
<h3>Option A:</h3>
Option A is not a solution.
<h3>Option B:</h3>
Option B is not a solution.
<h3>Option C:</h3>
Option C is a solution.
Hope this helps.
This graph shifted down 4 units would be y = x^2 - 2.
Different shifts in standard graphs each have to be done in their own way. Shifting up and down is done by manipulating the y-intercept, which is the number at the end of the equation. Since we started at +2 and it is going down 4, it brings us to -2.
Answer:
1000
Step-by-step explanation:
To find the value of a digit in a number, set all the other digits to zero.
The value of 7 in 7042 is 7000.
The value of 7 in 427 is 007 = 7.
Then the question is "how many times larger is 7000 than 7?" That result is found by dividing 7000 by 7:
7000/7 = 1000
The 7 in 7042 is 1000 times larger than the 7 in 427.
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<em>Another way to consider this</em>
The 7 in 7042 is in the "thousands" place. The 7 in 427 is in the "ones" place. The thousands place is 3 places to the left of the ones place. Each place moved to the left increases the value by a factor of 10, so the value of a digit in the thousands place is 10×10×10 = 1000 times that of the same digit in the ones place.
