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Varvara68 [4.7K]
3 years ago
15

What is the simplified expression for the expression below?

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0
The answer is #1. 4x - 43
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Plz help! Don’t understand this question
solniwko [45]

Answer:

11.91

Step-by-step explanation:

The question says there is a new line that connects V and T. If this line is drawn, the diagram would have a right-angle triangle. This triangle is called TUV.

In triangle TUV, the side length created by the points VT is the hypotenuse.

For right-angle triangles, you can use the Pythagorean theorem to find any side.

It's in the format side² + side² = hypotenuse².

To use the formula, you need to know the length of the other two sides. The length of these sides, because they are exactly horizontal or vertical, is found by subtracting the smaller coordinate from the other (that is not the same).

The lengths of other sides:

VU:

-3 is the same. The length is 3.5 - (-5.75) = 9.25

UT:

-5.75 is the same. The length is 4.5 - (-3) = 7.5

Substitute the lengths into the Pythagorean theorem:

a² + b² = c²

9.25² + 7.5² = c²  Simplify

141.8125 = c²  Find the square root of both sides to isolate c

c = 11.91  Final answer, length of VT

7 0
3 years ago
Which equation represents the line that passes through the points (2, 4) and (1, -3)?
zhannawk [14.2K]

Answer:

y = 7x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 4) and (x₂, y₂ ) = (1, - 3)

m = \frac{-3-4}{1-2} = \frac{-7}{-1} = 7, thus

y = 7x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 4), then

4 = 14 + c ⇒ c = 4 - 14 = - 10

y = 7x - 10 ← equation of line

6 0
4 years ago
Can someone help me get the answer for this? i don’t understand it, any help is appreciated :))
Dima020 [189]

A circle is a geometric object that has symmetry about the vertical and horizontal lines through its center. When the circle is a unit circle (of radius 1) centered on the origin of the x-y plane, points in the first quadrant can be reflected across the x- or y- axes (or both) to give points in the other quadrants.

That is, if the terminal ray of an angle intersects the unit circle in the first quadrant, the point of intersection reflected across the y-axis will give an angle whose measure is the original angle subtracted from the measure of a half-circle. Since the measure of a half-circle is π radians, the reflection of the angle π/6 radians will be the angle π-π/6 = 5π/6 radians.

Reflecting 1st-quadrant angles across the origin into the third quadrant adds π radians to their measure. Reflecting them across the x-axis into the 4th quadrant gives an angle whose measure is 2π radians minus the measure of the original angle.

7 0
3 years ago
Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat
likoan [24]

F+G:

F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}

Then, add the elements that occupy the same position:

H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}

Solve

H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}

So, we find the element at address h31:

H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}

In this case, position h31 is - 8.0

8 0
1 year ago
Shawna lives in an apartment 9 4/5 miles from the hospital where she works. Her brother rents a room in a house 7 2/5 miles from
tamaranim1 [39]

Answer:

2 2/5 miles

Step-by-step explanation:

6 0
3 years ago
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