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Vikki [24]
3 years ago
15

A pizza has a diameter of 16 inches. What is the area of the pizza? Leave answer in terms of π.

Mathematics
2 answers:
Elina [12.6K]3 years ago
8 0
Area = \pir^{2}  and diameter is just 2 x radius
Since your diameter is 16, you just divide by 2 to get the radius, 8. 
So, plug in your values to get:
\pi8^{2}
So...
64\pi tex] in^{2} [/tex]
egoroff_w [7]3 years ago
7 0

Answer: I think 64 in2

Step-by-step explanation:

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When you say comparing do you mean dividing or just comparing

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3 years ago
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Is 49 a perfect square yes or no
Romashka [77]

Answer:

Yes

Step-by-step explanation:

7 x 7 = 49

4 0
3 years ago
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Jon recently drove to visit his parents who live 280 miles away. On his way there his average speed was 9 miles per hour faster
Luba_88 [7]

Answer:

11 mph and 20 mph

Step-by-step explanation:

Represent his average speed going by r1 and his average speed returning by r2.  We know that r1 = r2 + 9.

Recall that distance = rate times time, so time = distance / rate.

Time spent going was (280 mi) / r1, or (280 mi) / (r2 + 9 mph).

Time spend returning was (280 mi) / r2.

The total time was 14 hrs, so (280 mi) / (r2 + 9 mph) + (280 mi) / r2 = 14 hrs

Note that there is only one variable here:  r2.  Find r2, and then from r2, find r1:

Dividing all 3 terms by 14 hrs yields:

  20            20

---------- + ----------- = 1

r2 + 9         r2

The LCD here is r2(r2 + 9).  Thus, we have:

      20r2                    (r2 +  9)(r2)

------------------- = 1 or  ------------------

 (r2 +  9)(r2)               (r2 +  9)(r2)

Then 20(r2) = (r2)^2 + 9(r2).  This is reducible by dividing all terms by r2:

20 = r2 + 9, or 11 = r2.  Then r1 = 11 + 9, or 20.

The two rates were 11 mph and 20 mph.

8 0
3 years ago
Please help, i need to raise my grade
Dmitrij [34]

Answer:

r=\dfrac{v^2}{a}

Step-by-step explanation:

To isolate r, we're going to need to do some algebraic manipulation.

a=\dfrac{v^2}{r}

Multiply both sides by r:

a\cdot r=v^2

Divide both sides by a:

r=\dfrac{v^2}{a}

Hope this helps!

5 0
3 years ago
Please help STRUGGLING with math few math questions! Ty
-BARSIC- [3]

Question 1:


F(x) and g(x) are like variables, just plug into the equation.


f(x) + g(x) = (x + 6) + (12x - 7)


x+6+12x-7 = 13x-1


Question 2: f(3) + g(-1)


You plug in the x-values into the equation, and then take the answer and add them together.


f(3) = 3+4

g(-1) = 12(-1)-6


f(3) = 7

g(-1) = -18


7 + (-18) = -11


Question 3:


This is similar to question 1, plug in the variables and simplify.


9x - (7x+3)


Remember to distribute the "-"


9x - 7x - 3

2x - 3

6 0
3 years ago
Read 2 more answers
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