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goldenfox [79]

Answer:

Step-by-step explanation:

$12000(1+\frac{.12}{4})^{4*45}=2454040.31463\\=2454040$

7 0

2 years ago

on this american flag the width of the blue rectangle is 2/5 the width of the red and white stripes. What fraction of the area o

Gnesinka [82]

The area of the blue rectangle is 8/11 of the flag

The area of a shape is the amount of space it occupies

The width is given as:

$Width = \frac 25$

<h3>Blue region </h3>

The blue region of the American flag has a dimension of 8 by 11 stars.

So, we have:

$8 : 11 = x : \frac 25$

Where x represents the length of the blue region.

Express the ratio as fractions

$\frac{8 }{ 11} = x \div \frac 25$

Multiply both sides by 2/5

$\frac{8 }{ 11} \times \frac 52= x$

$\frac{20}{ 11} = x$

Rewrite as:

$x =\frac{20}{ 11}$

The area is then calculated as:

$Area =\frac{20}{ 11} \times \frac 25$

$Area =\frac{40}{ 55}$

Simplify

$Area =\frac{8}{ 11}$

Hence, the area of the blue rectangle is 8/11 of the flag

Read more about areas at:

brainly.com/question/14137384

3 0

3 years ago

You have been invited to be part of the planning committee for the County Fair. In order to be an effective member you will need

kakasveta [241]

Firstly let's find the dimension of this large rectangle:(given)

Area of Rectangle = 660 x 66 =43,560 ft²

And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²

We know that the 20 acres form a rectangle. We need to know what is their disposition:

1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS

Note that W=66 & L=666 = 43,956 ft²/ unit )

lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or

2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)

3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.

4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly

5 0

4 years ago

Lines AB and EB share a common point at B therefore we say that these lines

Brut [27]

2 lines in a plane can have these positions:

i) they can be parallel, if they share no common point.

ii) are intersecting, if they have one common point.

ii) they are coincident if they have 2 common points.

AB and EB share 1 common point, B, therefore they are Coincident.