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Vlad [161]
3 years ago
7

HURRY PLEASE What is the solution of the system 4x+3y=6 2x+2y=5

Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0
4x + 3y = 6
2x + 2y = 5

4x + 3y = 6
4x + 4y = 10

4x + 4y = 10
4x + 3y = 6

(4 - 4)x + (4 - 3)y = 4
y = 4

2x + 2y = 5
2x + 8 = 5
2x = -3
x = -3/2 or -1 1/2

x = -3/2, y = 4
jolli1 [7]3 years ago
7 0
The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I

The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II

Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4

Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2

From the above calculations:
x = -3/2
y = 4
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