Find slope through (3,16) and (8,18)

Monica bought a package of 434 party favors to give to the guests at her birthday party. She calculated that she could give 9 pa

nydimaria [60]

Answer:

so meh answer is

Step-by-step explanation:

4 0

3 years ago

A manufacturer knows that their items have a normally distributed lifespan, with a mean of 8.4 years, and standard deviation of

QveST [7]

Answer:

7.35 years

Step-by-step explanation:

Given that :

mean = 8.4

standard deviation = 0.6

From the negative z tables, the corresponding data for 0.04 = -1.75

So, using the z-score formula:

$z = \dfrac{x - \mu}{\sigma}$

$-1.75 = \dfrac{x - 8.4}{0.6}$

-1.75 × 0.6 = x - 8.4

- 1.05 = x - 8.4

x = -1.05 + 8.4

x = 7.35 years

the shortest lifespan will last less than 7.35 years

∴ the longest 4% will have lifespans longer than x = 8.4 + 1.75(0.6)

= 9.45 years

3 0

3 years ago

For the given maximization problem, (a) determine the number of slack variables needed, (b) name them, and (c) use slack var

sergij07 [2.7K]

Answer:

a) 2

b) s₁ and s₂

c) First linear equation: 5*x₁ + 8*x₂ + 10*x₃ + s₁ = 173

Second linear equation: 5*x₁ + 4*x₂ + 17*x₃ + s₂ = 254

Step-by-step explanation:

The problem statement, establishes two constraints, each one of them will need a slack variable to become a linear equation, so the answer for question

a) 2.

b) The constraints are: s₁ and s₂

c) First constraint

5*x₁ + 8*x₂ + 10*x₃ ≤ 173

We add slack variable s₁ and the inequality becomes

5*x₁ + 8*x₂ + 10*x₃ + s₁ = 173

The second constraint is:

5*x₁ + 4*x₂ + 17*x₃ ≤ 254

We add slack variable s₂ and the inequality becomes

5*x₁ + 4*x₂ + 17*x₃ + s₂ = 254

7 0

3 years ago

Read 2 more answers

Could someone help me? Plz

arsen [322]

4, yes, 1
5, no?, 0
6, yes, 6

4 0

3 years ago

If your good with set theory, i need help with the first four questions!

Nat2105 [25]

1. D: The overlap of the two sets represents the intersection, which is the set of elements common to both sets M and C. In this case, it's the set {4, 5, 6}.

2. D: P is the set of the first 100 multiples of 8 (8*1 = 8, 8*2 = 16, and so on)

3. C: n(A) represents the number of elements in the set A. When

$n(A\cup B)=n(A)+n(B)$

that means the sets A and B are disjoint, represented by the two circles with no overlap.

4. E:

$A\cup B$ is the set of elements belonging to either set A or B. The three elements of A are all in B, so A is a subset of B. This means $A\cup B=B$ .

Because A is a subset of B, we have $A\cap B=A$ .

$(A\cup B)'$ is the complement of $A\cup B$ , which refers to the set of elements *not* belong to $A\cup B$ . These are all the numbers in U that are not in this union, which would be $(A\cup B)'=\{3,13\}$ .

Because we know $A\cup B=B$ , we have $(A\cup B)'=B'$ .

7 0

3 years ago