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daser333 [38]
3 years ago
13

The width of a rectangular pool is 5 meters longer than the length. The perimeter of the pool is 58 meters. Use and equation to

find the pools length.
Mathematics
1 answer:
garri49 [273]3 years ago
8 0
The perimeter of a rectangular pool = 2l + 2w

If the width is 5m longer than the length, 

Then Perimeter = 2(l + 5) + 2l
                          = 4l + 10  {THE EQUATION}

Since Perimeter = 58 m
Then 4l + 10 = 58 m

⇒  l  =  12 m

Thus the Length of the Pool = 12 m
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Answer:

a) $14.37 sales tax

b) $25.13 left on gift card

Step-by-step explanation:

Purchases: 78.50 + 32.00 = 110.50

Sales tax: 13%:

1% of 110.50 = 1.1050

1.1050 x 13 = 14.365

rounded to 2 decimal places: $14.37

Total cost: 110.50 + 14.37 = $124.87

Gift card: 150.00 - 124.87 = 25.13

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3 years ago
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
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  • brainly.com/question/13174259

#learnwithBrainly

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16 per 14 equals 224
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Helga [31]
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3 years ago
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Answer:

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perpendicular line: (8/7)

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4 0
3 years ago
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