The answer to the equation. is 2
Answer:
y=Ae^(1.25t)
Step-by-step explanation:
From the expression y=Ae^kt
After two days of the experiment, y = 49 million, t=2
After four days of the experiment, y= 600.25 million, t=4
A is the amount of bacteria present at time zero and t is the time after the experiment (in days)
At t=2 and y =49
49=Ae^2k…………….. (1)
At t=4 and y = 600.25
600.25=Ae^4k………… (2)
Divide equation (2) by equation (1)
600.25/49=(Ae^4k)/(Ae^2k )
12.25=e^2k
Take natural log of both sides
ln(12.25) =2k
2.505 =2k
k=1.25
The exponential equation that models this situation is y=Ae^(1.25t)
Answer: w = 7, x = 6
Step-by-step explanation: Solve by substitution
W + b = 13
rewrite as b = 13 - w and substitute that value for b in the second equation
6.5w + 2b = 57.5 Then solve for w
6.5w + 2(13-w) = 57.5 . Distribute
6.5w + 26 - 2w = 57.5 . Subtract 26 from both sides. Combine like terms and simplify
6.5w - 2w = 57.5 - 26
4.5w = 31.5 Divide both sides by 4.65
w = 7 . Substitute 7 for w in the first equation and solve for b
7 + b = 13 . Subtract 7 from both sides
b = 6
Answer:
the answer is C mean absolute deviation
