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elena-14-01-66 [18.8K]
3 years ago
5

Please help asap! Number 2 , picture is included! (10 points)

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
4 0
So, first, we know that the whole angle must equal 90 because there's a right angle symbol, and right angles equal 90 degrees.

So, 43 + x + 3 must equal 90.

Or, 46 + x = 90

Then subtract 46 from both sides.

x = 90 - 46

x = 44

These would also be adjacent angles because they share the same vertex.
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3 years ago
I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know
azamat

By definition of conditional probability,

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}

=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}

Assuming a standard 6-sided fair die,

  • if X_1=4, then X_1+X_2=7 means X_2=3; otherwise,
  • if X_2=4, then X_1=3.

Both outcomes are mutually exclusive with probability \frac1{36} each, hence total probability \frac2{36}=\frac1{18}.

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs \frac6{36}=\frac16 of the time.

Then the probability we want is

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13

6 0
3 years ago
Uncle percy sold t-shirts at the show. Now he only have 10% of the t-shirts he started with. If he has 25 t-shirts now, how many
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Percy used to have 100% of the shirts (before he started selling them). Since then, he has given away 90% of the shirts and is now left with only 10% of what he used to have. He currently has 25 shirts, meaning that 25 is 10% of what he had.

Lets set up a proportion:

25 shirts : 10%
x shirts : 100%

x = 25*100 / 10
x = 2500 / 10
x = 250 shirts
Percy started off with 250 shirts.


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I am so sorry if this is wrong but I believe that the answer is a. $285.

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