I hope this helps you
1=3
2=4
1 and 2
3 and 4 adjacent
Answer: Our required probability is 
Step-by-step explanation:
Since we have given that
Number of coins = 3
Number of coin has 2 heads = 1
Number of fair coins = 2
Probability of getting one of the coin among 3 = 
So, Probability of getting head from fair coin = 
Probability of getting head from baised coin = 1
Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

Hence, our required probability is 
No, the answer is not 
x=1/2
i hate the minimum word count
no one comes on here to learn how to do it, we come on here to get answers
Answer:
Step-by-step explanation:
At first,
Let start writing the squares of number 0 to 10,
0²=0
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
Now,
According to your question,
- The two numbers should be square numbers
- They should be greater than 1.
- Their sum should be 100.
Hence, your given conditions matches with the numbers 64 and 36.
Therefore, the numbers are 64 and 36.
- 64 and 36 are greater than 1.
- 64 is a square of 8 and 36 is the square of 6.
- 64+36=100