Answer:
3^2 + 4^2= 25
Step-by-step explanation:
Answer:
x=10 and y=12
Step-by-step explanation:
To solve this quadratic equation we will use two method
1. Elimination method
2. substitution method
first of we use elimination method
we either eliminate x or y
we will be eliminating y
83x-20y=590..........(eq1)
60x+18y=816...........(eq2)
y will be eliminated by multiplying
(eq1) by 9
(eq2) by 10
which will give
747x-180y=5310.........(eq3)
600x-180y=8160.........(eq4)
see that y has the same value that is (-180y and +180y)
so to eliminate y completely you have to add eq1 and eq2 because if you don't add them together you wont eliminate y
747x-180y=5310
+
600x+180y=8160
=
1347x+0=13470
1347x=13470
x=13470/1347
x=10
Now to find y we use substitution method ie put x=10 in any of the equation above(eq1,eq2,eq3, eq4) you will get the same answer
eq1
83x-20y=590..... where (x=10)
83(10)-20y =590
830-20y=590
like terms
-20y=590-830
-20y= -240
divide both sides with -20
y= -240/-20
y=12
OR
eq2
60x+18y=816..... where x=10
60(10)+18y=816
600+18y=816
like term
18y=816-600
18y=216
y=216/18
y= 12
or eq3 or eq4 you will still get the same answer......
Answer:
the 7th
0.007805 or 59 / 756
Step-by-step explanation:
To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.
to do this, divide the total pounds by the number of dogs
on the 14th
3/8 ÷ 35 =
3/8 x 1/35 = 3/280
on the 7th
1/2 ÷ 27 =
1/2 x 1/27 = 1/54
to determine which fraction is larger multiply each by 100 to determine its percent
3/280 x 100 = 1.071
1/54 x 100 = 1.852
1/54 is larger. Thus, more pounds was needed on Friday the 7th
the difference between these fractions should be determined
- 
=
= 59 / 756
Answer:
4.2
Step-by-step explanation: