Answer:
The functional expression can be simplified by substituting the given value in the function in place of the variable.
For example, if {eq}f(x)=x^{2} {/eq} be a function then {eq}f(2) {/eq} is determined by plugging {eq}x=2 {/eq} in the function.
Step-by-step explanation:
The given function is:
{eq}f(x) = 4x^{2} + 2x {/eq}
Let {eq}y=\frac{f(x + h) - f(x)}{h} {/eq} then we have:
{eq}\\\\\begin{align*} y & = \frac{4(x+h)^{2} + 2(x+h)-(4x^{2}+2x)}{h} \\\\ & = \frac{4(x+h)^{2} + 2(x+h)-(4x^{2}+2x)}{h} \\\\ & = \frac{4(x^{2}+2xh+h^{2}) + 2x+2h-4x^{2}-2x}{h} \\\\ & = \frac{4x^{2}+8xh+4h^{2}+ 2h-4x^{2}}{h} \\\\ & = \frac{8xh+4h^{2}+ 2h}{h} \\\\ & = \frac{h(8x+4h+2)}{h} \\\\ & = 8x+4h+2 \\\\\end{align*} {/eq}
Answer:
only after you have done this an infinite amount of times, so, no not really.
Step-by-step explanation:
This is a geometric series also used in Zeno's paradox: Achilles and the tortoise.
750 divided by 600 x 100= 125%
