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3 years ago

7

The ratio of the number of cookies to the number of pastries in a box is 3:2. Which table shows the possible amounts of cookies

and pastries in a box, given the ratio?

1 answer:

artcher [175]3 years ago

6 0

Answer:

3:2

6:4

12:8

24:16

48:32

idk how many u need but thats some!

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Place a set of parentheses in the expression so that its value is 33. 48-5+2x3+6

Xelga [282]

The parentheses must be placed here <span>48 - (5 + 2) * 3 + 6 in order for the equation to equal 33. </span>

4 0

4 years ago

144 flowers in a vase the ratio of yellow to pink flowers is 5 to 6 how many yellow flowers are in the vase

azamat

$\frac{5}{11} \times 144 \: is \: the \: amount \: of \: yellow \: flowers \\ \\ \frac{5}{11} \times 144 = 65.45 = 65$
therfore there is 65 yellow flowers

4 0

3 years ago

Find 4 geometric means between -5 and -125.

balandron [24]

The geometric means between -5 and -125 is; 25

<h3>How to find the geometric mean?</h3>

To find the geometric mean between two numbers, we simply find the square root of the product of the two numbers.

For example, geometric mean between A and B is;

G.M = √(A * B)

Thus, geometric mean between -5 and -125 is;

G.M = √(-5 * -125)

G.M = √625

G.M = 25

There could be other geometric means between this like;

G.M = √(-5 * -45) = 15

Or GM = √(-10 * -40) = 20

Read more about geometric mean at; brainly.com/question/17266157

#SPJ1

8 0

2 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago

Please help I really need it

masha68 [24]

Answer:

There's 2: I've attached an image.

Step-by-step explanation:

Lines of symmetry are found when you fold it, and it's exactly the same on both sides of the line that you folded it.

If your teachers ask, no, it cannot be diagonal. The triangles would not match up.

6 0

2 years ago

Read 2 more answers