Answer:
976 square cm
Step-by-step explanation:
Area of one 2d triangle face: (24*14)/2=168 square cm
Area of both 2d triangles faces: 168 + 168 =336 square cm
Area of one side: 25*10=250 square cm
Area of both sides: 250+250=500
Area of base: 14*10=140 (since it's a triangular prism, there's only one base)
Surface Area: 336+500+140=976 square cm
Hope this helps! :)
The box does not let me write in it....
<span>.5-.625, C=.5625 therefore C would be the answer. I found this by taking all of the fractions and dividing the numerator by the denominator and then lining up all of the decimals till one worked out.
</span>Hope it works
Answer:
52.56% probability that eight or more of the flights will arrive on time.
Step-by-step explanation:
For each flight, there are only two possible outcomes. Either it is on time, or it is not. The probability of a flight being on time is independent from other flights. So we use the binomial probability distribution to solve this question.]
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
At a certain airport, 75% of the flights arrive on time.
This means that
A sample of 10 flights is studied.
This means that
Find the probability that eight or more of the flights will arrive on time.
In which
52.56% probability that eight or more of the flights will arrive on time.
Step-by-step explanation:
Here we have
f
(
x
)
=
2
x
2
(
x
2
−
9
)
, which can be factorized as
f
(
x
)
=
2
x
2
(
x
+
3
)
(
x
−
3
)
As there is no common factor between numerator and denominator, there s no hole.
Further vertical asymptotes are
x
=
−
3
and
x
=
3
and as
f
(
x
)
=
2
x
2
(
x
2
−
9
)
=
2
1
−
9
x
2
, as
x
→
∞
,
f
(
x
)
→
2
, hence horizontal asymptote is
y
=
2
.
Observe that
f
(
−
x
)
=
f
(
x
)
and hence graph is symmetric w.r.t.
y
-axis. Further as
x
=
0
,
f
(
x
)
=
0
. Using calculas we can find that at
(
0
,
0
)
there is a local maxima as
d
y
d
x
=
−
36
x
(
x
2
−
9
)
2
and at
x
=
0
it is
0
. Further while for
x
<
−
3
and
x
>
3
, function is positive, for
−
3
<
x
<
3
function is negative.
Now take a few values of
x
say
{
−
10
,
−
7
,
−
4
,
−
2
,
−
1
,
1
,
2
,
4
,
7
,
10
}
and corresponding values of
f
(
x
)
are
{
2
18
91
,
2
9
20
,
4
4
7
,
−
1
3
5
,
−
1
4
,
−
1
4
,
−
1
3
5
,
4
4
7
,
2
9
20
,
2
18
91
}