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TiliK225 [7]
3 years ago
6

A plaine's altitude changes by -1,000 feet. Is the plane going up or down?

Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0
The plane is going down.
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Find the pattern, then write the next two letters.<br> J, F, M, A, M,_, _
RoseWind [281]

Answer:

its answer J,F,M,A,M,J,J

Step-by-step explanation:

<h3>its a name of months next 5 words is A,S,O,N,and D</h3>
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1. (5x2-2x+3) + (x2+x+2)
antiseptic1488 [7]
The answer is: x^2-x+15
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What is the length of the figure?
nadezda [96]
There are two ways to do this. One is by adding up the squares, which takes a while. The other way is if you notice that the length along the bottom is the same as that long the top, and the same is true for the sides. While it does not appear this way at first, imagine that that was the floor plan of a house. If you looked at it from the side, you wouldn't see the dent in the corner, only one side. Since the length of the top is 13 units, from -7 to 6, and the side is also 13 units, from -6 to 7, the answer is 13*2 + 13* 2 = 26 + 26 = 52

52 units long.
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3 years ago
What is one way to find the number of liters in 8 kiloliters?
zhuklara [117]

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8000 liters

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A rectangular page is to contain 24 sq. in. of print. The margins at the top and bottom of the page are each 1.5 inches. The mar
suter [353]

Answer:

Dimensions of page should be width of 6 inches and height of 9 inches

Step-by-step explanation:

Let x be the width of the printed part in inches

Let y be height of the printed part in inches.

Thus, Area of printed part; A = xy

And area of printed part is given as 24.

Thus, xy = 24

Making y the subject, we have;

y = 24/x

Now, the question says the top and bottom margins are 1.5 inches.

Thus, width of page = x + 1 + 1 = x + 2

And also the margins on each side are both 1m in length, thus the height of page will be:

y + 1.5 + 1.5 = y + 3

So area of page will now be;

A = (x + 2)•(y+3)

From earlier, we got y = 24/x

Thus,plugging this into area of page, we have;

A = (x + 2)•((24/x)+3)

A = 24 + 3x + 48/x + 6

A = 30 + 3x + 48/x

For us to find the minimum dimensions, we have to find the derivative of A and equate to zero

Thus,

dA/dx = 3 - 48/x²

Thus, dA/dx = 0 will be

3 - 48/x² = 0

Multiply through by x²:

3x² - 48 = 0

Thus,

3x² = 48

x² = 48/3

x = √16

x = 4 inches

Plugging this into y = 24/x,we have;

y = 24/4 = 6 inches

We want dimensions of page at x = 4 and y = 6.

From earlier, width of page = x + 2.

Thus,width = 4 + 2 = 6 inches

Height = y + 3 = 6 + 3 = 9 inches

So dimensions of page should be width of 6 inches and height of 9 inches

4 0
3 years ago
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