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Fudgin [204]
3 years ago
8

All fractions equivalent to 27/81

Mathematics
1 answer:
Strike441 [17]3 years ago
3 0
There is more than a trillion of equivalent fractions to 27/81, you just need to divide of multiply that number to any other numbers, but not 1 and 0, it can be negative number also
Ex: 1/3, 3/9, 54/12, 81/243, etc...
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Four goats eat 8 tin cans in one hour. How long should it take 8 goats to eat 4 tin cans?
quester [9]

Answer:

15

Step-by-step explanation:

15 minutes

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3 years ago
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9. Find (f.g)(a) if f(a) = . and g(a) = 2². Fully simplify your answer.
Aleks04 [339]

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3 years ago
Refer to the various selling prices of various homes in a community that follow the normal distribution with mu (population mean
blsea [12.9K]

Answer:

0.43715

Step-by-step explanation:

We solve using z score calculator

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = $276,000

σ is the population standard deviation = 32,000

For x = $276,000

z = 276,000 - 276,000/32000

z = 0

Probability value from Z-Table:

P(x = 276000) = 0.5

For x = $325,000

z = 325,000 - 276,000/32000

z = 1.53125

Probability value from Z-Table:

P(x = 325000) = 0.93715

The probability that the next house in the community will sell for between $276,000 and $325,000 is

P(x = 325000) - P(x = 276000)

= 0.93715 - 0.5

= 0.43715

8 0
3 years ago
879,100 rounded to the nearest ten thousand
faust18 [17]
880,000 is the answer
5 0
3 years ago
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I will mark brainliest IF CORRECT
umka2103 [35]

Answer:

1 - (π/6) - (√3/4)

Step-by-step explanation:

First, calculate the area of ABCD. That's just 1*1 = 1 un^{2}

Then, we are told that arcs BD and AC are circular, meaning they are portions of a circle. Therefore, let's redraw this image a little. Look below for the image.

Essentially, what I've done is created an equilateral triangle and two sectors. You may be wondering why the triangle is equilateral. Well, we firstly know it's isosceles because the two original arcs are circular and congruent. Their overlap creates two congruent lines that can be extend from point M to the vertices A and D. These two lines also happen to be radii of the quarter circles because the two sectors have AM AND AD as radii. AM and AD = 1, so AMD is an equilateral triangle.

Draw altitude OD. This is a right angle. Since equilateral triangles are also isosceles triangles, and isosceles triangles have the property of sharing the median to base and altitude to base, we can say that OD = \frac{1}{2} AD = \frac{1}{2}. MD = 1, so this triangle is a 30-60-90 triangle. Why? This is because of the 30º angle converse theorem. The shorter leg is half of the hypotenuse MD, so <OMD is a 30º angle, making <ODM a 60º angle and inevitably <MDC a 30º angle (because <D is a right angle) and <ABM as well because the two sectors are congruent.

Because m<ABM = m<MDC = 30º, these two sectors are 30/360 of the individual circles or 1/12 of the original circles, which have areas of π (because 1^2*π = π). Each is 1/12π, combined they are 1/6π.

The area of the equilateral triangle is √3/8. This is because MO can be calculated, using the 30-60-90 ratios, to be √3/2. (1 * √3/2)/2 = (√3/2)/2 = √3/4; this uses the area of a triangle. Now, time to calculate the shaded area.

The area of the square is 1, the area of the sectors π/6, and the equilateral triangle √3/4. Subtract the equilateral triangle and sectors' areas from the area of the square to be left with the remaining shaded part. 1-(π/6)-(√3/4) is your final answer. To put that a little more cleanly below in the image.

Hope this helps, have a great day.

3 0
2 years ago
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