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Vilka [71]
4 years ago
5

What is the range of the relation?

Mathematics
2 answers:
zalisa [80]4 years ago
8 0

Answer:

D

Step-by-step explanation:

zavuch27 [327]4 years ago
5 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em><em>.</em>

<em>Additional</em><em> </em><em>Information</em><em>:</em>

<em>The</em><em> </em><em>second</em><em> </em><em>components</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>relation</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>range</em><em> </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>. </em><em>.</em>

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<u>Given</u>:

Given that the function p(x)=\left\{\begin{array}{ll}\frac{1}{4} x^{2}+1 & \text { if } x \leq 3 \\\frac{1}{4} x+2.5 & \text { if } x>3\end{array}\right.

We need to determine the function to evaluate when x = -5.

<u>Function</u>:

The function is given two interval. The interval x\leq 3 means that x takes all values less than or equal to 3.

And the interval x>3 means that x takes all values greater than 3.

We need to determine the function that takes the limit when x = -5.

From the two limits, the limit x = -5 lie in the interval x\leq 3 because the interval takes all x values less than or equal to 3.

Hence, the function is p(x)=\frac{1}{4} x^{2}+1

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OlgaM077 [116]
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