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Vilka [71]
3 years ago
5

What is the range of the relation?

Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

D

Step-by-step explanation:

zavuch27 [327]3 years ago
5 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em><em>.</em>

<em>Additional</em><em> </em><em>Information</em><em>:</em>

<em>The</em><em> </em><em>second</em><em> </em><em>components</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>relation</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>range</em><em> </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>. </em><em>.</em>

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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil
Furkat [3]

Answer:

t = 5.25 seconds

Step-by-step explanation:

Given that,

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation:

h(t)=-16t^2+48t+190

It is assumed to find the time when the projectile will hit the ground. When the projectile hit the ground, its height is equal to 0 such that,

-16t^2+48t+190=0

It forms a quadratic equation such that,

t=\dfrac{-b+\sqrt{b^{2}-4ac } }{2a},\dfrac{-b-\sqrt{b^{2}-4ac } }{2a}\\\\t=\dfrac{-48+\sqrt{(48)^{2}-4\times (-16)(190) } }{2\times (-16)},\dfrac{-48-\sqrt{(48)^{2}-4\times (-16)(190) } }{2\times (-16)}\\\\t=-2.25, 5.25

So, the projectile will hit the ground at t = 5.25 seconds.

3 0
3 years ago
Read 2 more answers
Find the equation of the line whose x-intercept is 8 and y-intercept is -2. write the equation in slope-intercept form.
goldfiish [28.3K]
Find the slope, m = (change in y) / (change in x)

                     0-(-2)
Here, m = ------------- = 1/4
                     8 - 0
y-k = m(x-h) becomes         y+2 = (1/4)(x), or y = (1/4)x - 2

Then the desired equation is   y = (1/4)x - 2 (slope-intercept form)
7 0
3 years ago
Read 2 more answers
A recipe used 2/3 cup of sugar for every 2 teaspoons of butter. How much sugar was used per teaspoon of butter
myrzilka [38]

Answer:

2/3cups 2 teaspoons

(2/3 )cups/2teaspoons =1/3 cups per teaspoon

Answer= 1/3 cups per teaspoon

8 0
3 years ago
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Based on historical data, your manager believes that 41% of the company's orders come from first-time customers. A random sample
TEA [102]

Answer:

The probability that the sample proportion is between 0.35 and 0.5 is 0.7895

Step-by-step explanation:

To calculate the probability that the sample proportion is between 0.35 and 0.5 we need to know the z-scores of the sample proportions 0.35 and 0.5.

z-score of the sample proportion is calculated as

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of first time customers
  • p is the proportion of first time customers based on historical data
  • N is the sample size

For the sample proportion 0.35:

z(0.35)=\frac{0,35-0.41}{\sqrt{\frac{0.41*0.59}{72} } } ≈ -1.035

For the sample proportion 0.5:

z(0.5)=\frac{0,5-0.41}{\sqrt{\frac{0.41*0.59}{72} } } ≈ 1.553

The probabilities for z of being smaller than these z-scores are:

P(z<z(0.35))= 0.1503

P(z<z(0.5))= 0.9398

Then the probability that the sample proportion is between 0.35 and 0.5 is

P(z(0.35)<z<z(0.5))= 0.9398 - 0.1503 =0.7895

6 0
3 years ago
A number is chosen at random from 1 to 50. find the probability of selecting numbers greater than 3 and less than 39. How to sol
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Solve than first chose letter and bind
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3 years ago
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