Answer:
t = 5.25 seconds
Step-by-step explanation:
Given that,
A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation:

It is assumed to find the time when the projectile will hit the ground. When the projectile hit the ground, its height is equal to 0 such that,

It forms a quadratic equation such that,

So, the projectile will hit the ground at t = 5.25 seconds.
Find the slope, m = (change in y) / (change in x)
0-(-2)
Here, m = ------------- = 1/4
8 - 0
y-k = m(x-h) becomes y+2 = (1/4)(x), or y = (1/4)x - 2
Then the desired equation is y = (1/4)x - 2 (slope-intercept form)
Answer:
2/3cups 2 teaspoons
(2/3 )cups/2teaspoons =1/3 cups per teaspoon
Answer= 1/3 cups per teaspoon
Answer:
The probability that the sample proportion is between 0.35 and 0.5 is 0.7895
Step-by-step explanation:
To calculate the probability that the sample proportion is between 0.35 and 0.5 we need to know the z-scores of the sample proportions 0.35 and 0.5.
z-score of the sample proportion is calculated as
z=
where
- p(s) is the sample proportion of first time customers
- p is the proportion of first time customers based on historical data
For the sample proportion 0.35:
z(0.35)=
≈ -1.035
For the sample proportion 0.5:
z(0.5)=
≈ 1.553
The probabilities for z of being smaller than these z-scores are:
P(z<z(0.35))= 0.1503
P(z<z(0.5))= 0.9398
Then the probability that the sample proportion is between 0.35 and 0.5 is
P(z(0.35)<z<z(0.5))= 0.9398 - 0.1503 =0.7895