How do I find the critical points?
1 answer:
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
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Answer:
Step-by-step explanation:
Let's set up a proportion using the following setup.
We know 30 buses can carry 1,500 people.
We don't know how many people 5 buses can carry, so we say 5 buses carry x people.
Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.
Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.
5 buses can carry 250 people.
Answer:
See below.
Step-by-step explanation:
I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.
♦ The midline's length is the average of the lengths of the top and bottom parallel sides.
Use this equation and substitute values given in each problem, then solve for the missing information.
1. AL = x, CE = 9, OR = 5
2. AL = <em>m</em> - 4, CE = 15, OR = 17
3. OR = y + 5, AL = 15, CE = 18