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sladkih [1.3K]
3 years ago
8

Where are the lateral ventricles ?

Biology
2 answers:
Tresset [83]3 years ago
8 0
The 2 interventricular foramens (or foramina of Monro) connect the lateral ventricles with the third ventricle. The body of the lateral ventricle is connected with the occipital and temporal horns by a wide area named the atrium. The anterior or frontal<span> horn is located anterior to the interventricular foramen</span>
tino4ka555 [31]3 years ago
4 0
Each lateral ventricle resembles a C-shaped structure that begins at an inferior horn in the temporal lobe, travels through a body in the parietal lobe and frontal lobe, and ultimately terminates at the interventricular foramina where each lateral ventricle connects to the central third ventricle.



hope this helped
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A fossil is discovered that has only 12.5% of the carbon-14 that it would have had originally (when the animal was alive). If th
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Answer:

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Explanation:

The decay equation:

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N=N_0e^{-\lambda t}

Given that,

The half life of carbon - 14 is 5700 years.

For half life, N=\frac{1}{2} N_0

To find the value of  \lambda, we need to put the value of N and t in the decay equation.

\frac12N_0=N_0e^{-\lambda \times 5700}

\Rightarrow \frac12=e^{-\lambda \times 5700}             [ Divided N_0 both sides]

Taking ln both sides

\Rightarrow ln| \frac12|=ln|e^{-\lambda \times 5700}|

\Rightarrow ln| \frac12|={-\lambda \times 5700}

\Rightarrow \lambda= \frac{ln| \frac12|}{-5700}

\Rightarrow \lambda= \frac{ln|1|-ln|2|}{-5700}             [ ln|\frac mn|= ln |m|-ln |n|]

\Rightarrow \lambda= \frac{ln|2|}{5700}                      [ln 1= 0]

The fossil has only 12.5% of the carbon carbon-14 that it would have had originally.

So, N=\frac{12.5}{100} N_0

Then,

\frac{12.5}{100} N_0=N_0e^{-\frac{ln|2|}{5700}t

\Rightarrow \frac{12.5}{100} =e^{-\frac{ln|2|}{5700}t

Taking ln both sides

\Rightarrow ln|\frac{12.5}{100} |=ln|e^{-\frac{ln|2|}{5700}t}|

\Rightarrow ln|\frac{12.5}{100} |={-\frac{ln|2|}{5700}t}

\Rightarrow t=\frac{ ln|\frac{12.5}{100}|} {-\frac{ln|2|}{5700}}

\Rightarrow t=\frac{ ln|\frac{12.5}{100}|\times 5700} {-{ln|2|}}

\Rightarrow t=17,100

The fossil is 17,100 years old.

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