Answer:
No, the relation is not a function.
Step-by-step explanation:
<em>We know, 'A function is a relation which maps each point of the domain to a unique image'.</em>
It is given that, the relation is 'f(x) = temperature in Seattle Washington on that date' and the domain is '{x| x is a date, expressed in day/month/year}'.
Now, as the temperature does not remain same throughout the day.
So, we get that,
'For the same date, the value of f(x) is not unique'
Thus, the given relation is not a function.
B haha. Hope this works out for ya.
x^2-4x=60
<h2>In a meeting room for a business event, there are 4 fewer chairs laid out in each row than the number of rows. The total number of chairs in the room is 60.</h2><h2 />
If each row has the same number of chairs as rows, then there is x^2 chairs.
Because there is 4 fewer chairs in every row, for every row you minus 4 - 4x
There a 60 chairs in total.
x^2 - 4x = 60
Substitute a number into the formula to check:
If there are 10 rows:
x = 10
10^2 - 4(10) = 60
100 - 40 = 60.
The correct way to solve this equation would be:
7=5+3(x-4)
Distribute the Brackets.
3*x=3x
3*4=12
7=5+3x-12
Add like terms.
7=-7+3x
Add 7 to both sides.
(7)+7=(-7+3x)+7
14=3x
Divide both sides by 3.
(14)/3=(3x)/3
4.6667 or 14/3 =x
Both answers are incorrect.
Some the significant mistakes:
-Didn't follow BEDMAS
-How did 7=8(x-4) turn into 78=x-4?
Hope this helps.
-Benjamin
If you have any questions on what I did, just leave a comment.
I tried to add my second image but it won't allow me. So, the base is 6 that you're missing for question 6. Good luck.