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Salsk061 [2.6K]
3 years ago
15

A calculator was purchased for $29. The wholesale cost was $20. What was the percent markup?

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
If you would like to find the percent markup, you can calculate this using the following steps:

x% of $20 is $29
x% * 20 = 29
x/100 * 20 = 29
x = 29 * 100 / 20
x = 145%

145% - 100% = 45%

The correct result would be 45%.
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two wheels are rolled simultaneously. The radius of the smaller wheel is r feet and the radius of the larger wheel 2r feet. If b
Nuetrik [128]
The circumference of a circle is C=2πR, where R is the radius of the circle and π≈3.14.

So if we open the circumference of the circle into a straight line segment, the length of this segment is C=2πR≈2*3.14*R=6.28R

4 rotations mean 4 circumferences that is 4 segments of length 6.28R, 
which makes a linear distance of 4*6.28R=25.12R


i: the radius of the smaller wheel is R=r, thus it covers a distance of 25.12r feet

ii: the radius of the smaller wheel is R=2r, thus it covers a distance of  25.12*2r=50.24r (feet)

50.24r is twice 25.12r, thus the larger wheel traveled Twice the distance of the smaller one.


Answer: the larger covered twice the distance of the smaller.
6 0
3 years ago
Which property is illustrated by the following statement <br><br> 2x(6)=(6)2x
aleksandrvk [35]
Communicative prop of multiplication because the numbers are moving
7 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
-4 - 3= Please help if you know the answer please explane??
Doss [256]

Answer:

-7

Step-by-step explanation:

there is nothing to explain but anyways

-4 - 3 = -7

8 0
4 years ago
Read 2 more answers
In a game of checkers there are 12 red pieces and 12 black game pieces.Julio is setting up the board to begin playing. what is t
Bond [772]
Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24  or 1/2 (reduced)

However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23

Now multiply those possibilities: 
 1/2  x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row.  11/46 is the answer.  
4 0
3 years ago
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