tv-sets are rated by the screen size and the screen size comes from the length of its diagonal.
so a 57" TV has a 57" diagonal.
Check the picture below.
![\bf \stackrel{length}{4\left( \cfrac{57}{5} \right)}\implies \cfrac{228}{5}\implies 45\frac{3}{5}~\hfill \stackrel{width}{3\left( \cfrac{57}{5} \right)}\implies \cfrac{171}{5}\implies 34\frac{1}{5} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Area}{\cfrac{228}{5}\cdot \cfrac{171}{5}}\implies \cfrac{38988}{25}\implies 1559\frac{13}{25}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Blength%7D%7B4%5Cleft%28%20%5Ccfrac%7B57%7D%7B5%7D%20%5Cright%29%7D%5Cimplies%20%5Ccfrac%7B228%7D%7B5%7D%5Cimplies%2045%5Cfrac%7B3%7D%7B5%7D~%5Chfill%20%5Cstackrel%7Bwidth%7D%7B3%5Cleft%28%20%5Ccfrac%7B57%7D%7B5%7D%20%5Cright%29%7D%5Cimplies%20%5Ccfrac%7B171%7D%7B5%7D%5Cimplies%2034%5Cfrac%7B1%7D%7B5%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7BArea%7D%7B%5Ccfrac%7B228%7D%7B5%7D%5Ccdot%20%5Ccfrac%7B171%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B38988%7D%7B25%7D%5Cimplies%201559%5Cfrac%7B13%7D%7B25%7D)
We have to factor becasue
area=legnth times width
area=4x^2+28x+49
area=(2x+7)(2x+7)
area=(2x+7)^2
legnth =width
we arent' given area so we can't solve
but, , since it is a squaer room, legnth=width so √area=legnth=width
Answer:
Step-by-step explanation:
So we are assuming only the times listed count toward telling us how long the game was, so you just add the three numbers together. 155, 175 and 30
It would be C. The right one makes it look horrible compared to the other, if someone did not look at the graph.
