It the wiper blade (and arm) made a full rotation, 2 circles would be formed.
One small circle with radius
b, and a larger circle with radius
a+b.
The areas of these 2 circles are respectively:
![\pi b^2=\pi\cdot 5^2=25 \pi (in^2)](https://tex.z-dn.net/?f=%5Cpi%20b%5E2%3D%5Cpi%5Ccdot%205%5E2%3D25%20%5Cpi%20%28in%5E2%29)
and
![\pi (a+b)^2=\pi (14+5)^2=361\pi (in^2)](https://tex.z-dn.net/?f=%5Cpi%20%28a%2Bb%29%5E2%3D%5Cpi%20%2814%2B5%29%5E2%3D361%5Cpi%20%28in%5E2%29)
120° is 1/3 of a complete angle 360° which form a circle, so the areas formed by the arm of length b, and the arm + the wiper blade (a+b) are:
![\frac{25 \pi}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%20%5Cpi%7D%7B3%7D)
and
![\frac{361\pi}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B361%5Cpi%7D%7B3%7D%20)
in squared respectively.
the actual wiped area is
![\frac{361\pi}{3}-\frac{25 \pi}{3}= \frac{336\pi}{3}=112\pi \approx351.7](https://tex.z-dn.net/?f=%5Cfrac%7B361%5Cpi%7D%7B3%7D-%5Cfrac%7B25%20%5Cpi%7D%7B3%7D%3D%20%5Cfrac%7B336%5Cpi%7D%7B3%7D%3D112%5Cpi%20%5Capprox351.7%20)
(in squared)
Area of the window is 54*24= 1296 (in squared)
thus, the ratio of the wiped area to the whole area of the window is 351.7/1296=0.271
Converted to percentages, this is 27.1%
Answer: 27.1%
Answer:
73
Step-by-step explanation:
584/8
"nine less than" means we're subtracting 9: -9
"The quotient" means division. "Of a number and 8" Usually the numerator is listed first: x/8
that gives us