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Anuta_ua [19.1K]
3 years ago
7

There are 745 students going on a school field trip. Each bus can carry 46 students. How many buses should the school reserve? E

xplain your reasoning
Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:

17 buses

Step-by-step explanation:

745/46=16.19

but, as u can't have .19 of a bus u must reserve 17 buses . hope this helps pls mark brainliest! also i am on achallenge to see how many friends i can get on brainly so pls friend me

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Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
4 years ago
Find sin 0.<br> 16<br> 20<br> 12
Flura [38]

<em>Answer:</em>

<em>A 16/20</em>

<em>explanation: 772.malachi on insta</em>

<em>Sin: 16/20</em>

<em>Cos: 12/16</em>

<em>Tan: 16/12</em>

5 0
3 years ago
Geometric Series assistance
Levart [38]

we have been asked to find the sum of the series

\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}

As we know that a geometric series has a constant ratio "r" and it is defined as

r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}

The first term of the series is a_1=\left(\frac{1}{3}\right)^{1-1}=1

Geometric series sum formula is

S_n=a_1\frac{1-r^n}{1-r}

Plugin the values we get

S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}

On simplification we get

S_5=\frac{121}{81}

Hence the sum of the given series is \frac{121}{81}

5 0
3 years ago
Use the listing method to represent the following set.
Hatshy [7]

Answer:

b

Step-by-step explanation:

{x | x I, x ≥ 3}

6 0
4 years ago
Read 2 more answers
At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

y^2 – 2y – 1 = 0

Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
4 years ago
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