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bazaltina [42]
3 years ago
11

What is the value of Z

Mathematics
2 answers:
ale4655 [162]3 years ago
6 0
23 degrees is the value of Z :)
Gemiola [76]3 years ago
5 0
180 - (62+95) = 23 °
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Which annual subscription costs the most ?
Juli2301 [7.4K]

Answer:

fun for kids and family fun

Step-by-step explanation:

7 0
3 years ago
The figures below are similar. What is the value of x?(i didn't mean to chose an answer ;-;)
katrin [286]

Answer:

is 6 cm the value of x ?? if it is not .... then i also don't known ..sryy srry

8 0
3 years ago
Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
makkiz [27]

Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

p(x.y) =  \frac{x1 + x2}{2} . \frac{y1 + y2}{2}

p(8.5) = ( \frac{10 + x}{2} . \frac{8 + y}{2} )

Since they are equal,equating with their corresponding elements we get,

8 =  \frac{10 + x}{2}

or, 16 = 10 + x

or, x=16-10

Therefore, x = 6

Now,

5 =  \frac{8 + y}{2}

or, 10 = 8 + y

or, y = 2

Therefore, The coordinates of another point are B(6,2)

<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
4 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
4 years ago
PLEASE HELP!!!!!!
slava [35]

9514 1404 393

Answer:

  A: (3x +4)

  B: (4x +5y) × (4x -5y)

Step-by-step explanation:

<u>Part A</u>:

Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.

  9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²

The side of the square is 3x+4.

__

<u>Part B</u>:

The difference of squares is factored like this:

  a²-b² = (a +b)(a -b)

The given area expression is the difference of squares with ...

  a = 4x, b = 5y

so, the factorization is ...

  16x² -25y² = (4x +5y)(4x -5y)

The dimensions of the rectangle are (4x+5y) by (4x-5y).

3 0
3 years ago
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