The answer is choice D.
y = 2x
I will show two reasons why this equation is correct.
Let x = 1
y = 2(1)
y = 2
The first point in the table is (1,2).
In the table, x = 3 is the second choice.
y = 2(3)
y = 6
The second point in the table is (3,6).
Answer: y = 2x
Answer:
480 minutes would be the answer
Step-by-step explanation:
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
Answer:
It is a rational number
Step-by-step explanation:
It is a rational number because -6/7 is equal to -0.857142 repeating. And a rational number repeats.
Hope this helps☝️☝☝
Here is how you find the number of possible U.S Zip codes.
<span>Take note of this: There are 10 1 digit numbers: 0,1,2,3,4,5,6,7,8,9.
</span>And we have 5 slots. So in each slot, there can be 10 possible numbers.
So let's put 10 in each blank slot.
10, 10, 10, 10, 10.
Therefore, the final answer would be 100,000. There are 100,000 possibilities of different U.S zip codes. Hope this answer helps.
