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sattari [20]
4 years ago
12

if a number is multiplied by 7, the result is 182. the sum of that number's two digits is 8. define the variables and write the

system of equations that would be use to find the number. then solve the system and find the number
Mathematics
1 answer:
just olya [345]4 years ago
4 0
So, basically, what I would do is divide 182 by 7, you would then get x. And x's two digits equal 8. So 182/7=x -----> x+x=8 X equals the number that equals the first problem. And then split that number into two digits.
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3 years ago
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Genrish500 [490]

We need to find two relations, and use them to find the value of y when z = 15.

We will see that the value of y in that case is 4,860.

We know that <u>y  varies inversely with the square of  x</u>, also <u>y  is also proportional to the cube of  z</u>

Then we can write:

y = k/x^2

y = c*z^3

We also know that:

When x = 3, y = 80.

Replacing that in the first equation to find the value of k:

80 = k/3^2

80 = k/9

80*9 = k = 720

We also know that when x = 2, z = 5

From the first relation we have:

y = 720/2^2 = 720/4 = 180

Now we replace this in the equation of y and z:

y = c*z^3

180 = c*5^3

180 = c*125

180/125 = c = 1.44

Now we need to calculate y when z = 15, then we just need to replace z by 15 in the equation for y and z:

y = 1.44*(15)^3 = 4,860.

If you want to learn more, you can read:

brainly.com/question/2548537

8 0
3 years ago
Use the figure below to find the value of x and PT.
Alexxandr [17]

Answer:

x=2

PT=7

Step-by-step explanation:

set up the equation like this: PT=TQ

(4x-1)=(2x+3)

calculate to find x

x=2

put x into the equation for PT

4(2)-1=7

4 0
3 years ago
Notes on comparing and using Algebraic tiles<br><br> 5-10 steps
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Step-by-step explanation:

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2 years ago
future value of 10% savings from earnings of 36000 earns 6.25% annual interest compounded quarterly for 15 years​
hoa [83]

without further ado

10% of 36000 is simply 3600, we chopped a "0" off of it hmmm, ok so

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3600\\ r=rate\to 6.25\%\to \frac{6.25}{100}\dotfill &0.0625\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &15 \end{cases} \\\\\\ A=3600\left(1+\frac{0.0625}{4}\right)^{4\cdot 15}\implies A=3600(1.015625)^{60}\implies A\approx 9126.53

7 0
3 years ago
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